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	<title>Tim Cinel &#187; logic</title>
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	<link>http://www.timcinel.com</link>
	<description>Where I exercise freedom of speech</description>
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		<title>Parallelograms and Vectors</title>
		<link>http://www.timcinel.com/2008/parallelograms-and-vectors</link>
		<comments>http://www.timcinel.com/2008/parallelograms-and-vectors#comments</comments>
		<pubDate>Sat, 15 Mar 2008 14:40:53 +0000</pubDate>
		<dc:creator>Tim Cinel</dc:creator>
				<category><![CDATA[Maths]]></category>
		<category><![CDATA[geometry]]></category>
		<category><![CDATA[logic]]></category>
		<category><![CDATA[midpoint]]></category>
		<category><![CDATA[parallelogram]]></category>
		<category><![CDATA[solution]]></category>
		<category><![CDATA[vectors]]></category>

		<guid isPermaLink="false">http://www.timcinel.com/2008/parallelograms-and-vectors</guid>
		<description><![CDATA[&#8220;Again with the maths&#8230;&#8221; Thursday on the train home, I was trying to solve a maths exercise &#8211; I am given A, B and C. I was asked to solve D so that ABCD formed a parallelogram. Where did I start? Here&#8217;s what I originally thought: kBC = AD (The top and bottom edges should [...]]]></description>
			<content:encoded><![CDATA[<p>&#8220;Again with the maths&#8230;&#8221; Thursday on the train home, I was trying to solve a maths exercise &#8211; I am given A, B and C. I was asked to solve D so that ABCD formed a parallelogram. Where did I start? Here&#8217;s what I originally thought:</p>
<ul>
<li>kBC = AD (The top and bottom edges should be parallel)</li>
<li>|AB| = |CD| (The two sides would be the same length)</li>
</ul>
<p>I couldn&#8217;t think of any more rules to help me, so I gave made a note of it, then moved on. It wasn&#8217;t long until I&#8217;d be at it again, and this time I&#8217;d solve it.<span id="more-15"></span></p>
<p>Paul (again) mentioned that you could use the midpoint between the opposing vertices (A and C ) and (B and X). And that&#8217;s how I solved it <img src='http://www.timcinel.com/wp-includes/images/smilies/icon_smile.gif' alt=':)' class='wp-smiley' /> </p>
<p>Here is the proof&#8230;</p>
<p style="text-align: center"><img src="http://www.timcinel.com/wp-content/dsc01708.JPG" alt="Vector Geometric Solution" /></p>
<p style="text-align: center"><em>If A, B and C are known, solve D so ABCD forms a parallelogram.</em><br />
<em>Mathamatical Methods for Engineers and Scientists, p7, 1.2.3 Q3 </em></p>
<p><font color="#999999"><em>Blast my inferior logic!</em></font></p>
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		<title>Vectors &#8211; Finding a Midpoint Between Two Points</title>
		<link>http://www.timcinel.com/2008/vectors-finding-a-midpoint-between-two-points</link>
		<comments>http://www.timcinel.com/2008/vectors-finding-a-midpoint-between-two-points#comments</comments>
		<pubDate>Sat, 15 Mar 2008 12:12:02 +0000</pubDate>
		<dc:creator>Tim Cinel</dc:creator>
				<category><![CDATA[Maths]]></category>
		<category><![CDATA[logic]]></category>
		<category><![CDATA[understanding]]></category>
		<category><![CDATA[vectors]]></category>

		<guid isPermaLink="false">http://www.timcinel.com/2008/vectors-finding-a-midpoint-between-two-points</guid>
		<description><![CDATA[Being the complete twit I am, over the last three days I&#8217;ve spent about &#8230; one hour, maybe two &#8230; trying to work out the coordinates of the midpoint between two points on a 3 dimensional Cartesian plane, using vector addition. It&#8217;s all better now, though. In an example, I was given A(1,-1,3) and B(-2,7,-2)  [...]]]></description>
			<content:encoded><![CDATA[<p>Being the complete twit I am, over the last three days I&#8217;ve spent about &#8230; one hour, maybe two &#8230; trying to work out the coordinates of the midpoint between two points on a 3 dimensional Cartesian plane, using vector addition. It&#8217;s all better now, though.<span id="more-13"></span></p>
<p>In an example, I was given A(1,-1,3) and B(-2,7,-2)   and I needed to find the midpoint, P.</p>
<p>I was trying to work it out as if P was the same as 1/2(AB) but it&#8217;s <em>quite </em>obviously not because that&#8217;s only the vector position <em>from point A</em> to point P (halfway Between A and B). Rather, we were looking for the vector position <em>from the origin </em>to the point P. If it wasn&#8217;t for Paul, I might still be trying to calculate it like this!</p>
<p>Therefore,  the absolute vector position of point P (midpoint between a and B) can be deducted like:<br />
P = OA + 1/2 * (AB)</p>
<p>Here are the workings for the CORRECT solution <img src='http://www.timcinel.com/wp-includes/images/smilies/icon_smile.gif' alt=':)' class='wp-smiley' /> </p>
<p style="text-align: center"><img src="http://www.timcinel.com/wp-content/dsc01707.JPG" alt="Vector Addition - Find Vector Position of Midpoint" /></p>
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